WebkJ/kg↔Btu/oz 1 Btu/oz = 37.216004668376 kJ/kg » Calorie/pound Conversions: cal/lb↔J/g 1 J/g = 108.338676336 cal/lb cal/lb↔J/kg 1 cal/lb = 9.230314 J/kg cal/lb↔mJ/kg 1 cal/lb … WebOne calorie= 4.184 joules; 1 joule= 1 kg(m) 2 (s)-2 = 0.239005736 calorie. The specific heat capacity of water vapour at room temperature is also higher than most other materials. …
Did you know?
WebAssumptions1The air-standard assumptions are applicable. 2Kinetic and potential energy changes are negligible. 3Air is an ideal gas with constant specific heats. PropertiesThe properties of air at room temperature are cp= 1.005 kJ/kg·K, cv= 0.718 kJ/kg·K, R= 0.287 kJ/kg·K, and k= 1.4 (Table A-2). WebMar 11, 2024 · The specific heat of a gas at constant pressure is given by the following formula: where, Cp = specific heat = ? ΔQ = heat required = 522 KJ. ΔT = change in …
WebScience Chemistry 1. A certain ideal gas whose R = 278.6 J/kg.K and cp =1.015 kJ/kg.K expands isentropically from 1517 kPa, 288°6 to 965 kPa. For 454 g/s of this gas determine, (a) Wn, (b) V2, (c) ΔU and (d) ΔH 1. A certain ideal gas whose R = 278.6 J/kg.K and cp =1.015 kJ/kg.K expands isentropically from 1517 kPa, 288°6 to 965 kPa. WebDetermine the average Cp value in kJ/kgK of 1kg gas if 552 kJ of heat is necessary to raise the temperature from 300 K to 800 K making the pressure constant. Video Answer …
WebK&G mobile marketing messages may be sent using an automated dialing system. You are not required to consent to receive mobile messages to purchase goods or services from … WebEnthalpy of saturated liquid, h f = C p dT = 4 x (T sat - T 1) = 4 x (100 - 30) = 280 kJ/kg. Total enthalpy of liquid at exit of boiler, h = h f + xh fg = 280 + 0.9 x 2400 = 2440 kJ/kg. Net heat supplied to the boiler = 2440 kJ/kg. Download Solution PDF. Share on Whatsapp Latest ISRO Scientist ME Updates.
Webarrangement. For R=8.314 J mol-1K , C V =20.785 C P =29.099J mol-1 K-1 The initial and final conditions of the air are identical with those of Ex.1, where the molar volumes are given as: V 1 =0.02479 V 2 =0.004958m3 Moreover, since the initial and final temperatures are the same, then for all parts of the problem:
Web= 1.005 kJ/kg K, and k = 1.4). Using (II), ( ) 48.2% 10 1 1 1 1 1.4 1 0.4 1 2 = ... starry and nbaWebR134a properties: Tcr = 374.2 K, Pcr = 4.059 MPa, Cp* = 0.766 kJ/kg-K, MW = 102, R = 0.0815 kJ/kg-K; We are asked to calculate the compressor efficiency using generalized compressibility. Solution: To solve this problem, we can use the following steps: Determine the initial and final states of the refrigerant; peter rabbit fly upon his nosehttp://cecs.wright.edu/people/faculty/sthomas/htappendix01.pdf peter rabbit fly upon his nose youtubeWebK&G Fashion Superstore for Men's and Women's Clothing, Childrens', Shoes, & Accessories. Choose from Suits, Dress Shirts, Ties, & more in regular, big and tall, & … peter rabbit food ideasWebThe constant-pressure specific heats of these gases at room temperature are 1.039, 0.918, 1.8723, and 0.846 kJ/kg K, respectively. The air properties at room temperature are cp = 1.005 kJ/kg K, cv = 0.718 kJ/kg K, k = 1.4 (Table A-2a). Analysis We consider 100 kmol of this mixture. Noting that volume fractions are equal to the mole fractions ... peter rabbit food heroWebEngineering. Mechanical Engineering. Mechanical Engineering questions and answers. A piston-cylinder assembly contains a mixture of 0.45 kg of methane (CH4, M = 16.04 kg/kmol, cp = 2.2 kJ/kg K, cv = 1.68 kJ/kg K) and 0.35 kg of ethane (C2H6, M = 30.07 kg/kmol, cp = 1.7 kJ/kg K, cv = 1.42 kJ/kg K). The mixture is initially at 100 kPa, 320 K … peter rabbit food pouchesWebQuantity Value Units Method Reference Comment; Δ f H° liquid: 49. ± 0.9: kJ/mol: Review: Roux, Temprado, et al., 2008: There are sufficient high-quality literature values to make a good evaluation with a high degree of confidence. peter rabbit fork and spoon